Re: [xsl] sorting question

Subject: Re: [xsl] sorting question
From: "Margarit A. Nickolov" <man@xxxxxxxxxxxxxxx>
Date: Wed, 28 May 2003 12:35:41 +0300
lars_huttar@xxxxxxx said:
>   select="/*/sd:Service[sd:ServiceDescription/@ServiceName='Y'
> 	and ../sd:Service[sd:ServiceID &lt; current()/sd:ServiceID]]" 

it works.

> But even if this worked, I don't think this would really be a win because it
> could be much less efficient (order N*N) than your original approach (order N
> * log N for sorting).

I do not pursue any performance, just learning XSLT.

> Don't think I helped much but nobody else had replied.

Thanks a lot, it helped me.
                best regards, margarit nickolov.

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