Subject: RE: RE: [xsl] How to get output XML same as input XML? From: cknell@xxxxxxxxxx Date: Wed, 09 Jul 2003 16:24:42 -0400 |
Duhohh! I typed "identity template" first, then, in a fit of nincompoopery, I changed it. Well it seems that another list member has spilled the beans on the details of the identity template, but erred in suggesting xsl:copy, which does not copy attributes as xsl:copy-of does. -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: cknell@xxxxxxxxxx Sent: Wed, 09 Jul 2003 16:05:12 -0400 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] How to get output XML same as input XML? Why not just use the input XML? If you have a good answer for that, then search for "XSLT default template" and the xsl:copy-of element. -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: "Josh Hone" <icsad@xxxxxxxxxxx> Sent: Wed, 09 Jul 2003 15:49:17 -0400 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] How to get output XML same as input XML? Hi all - This is my first post on this list, but I have been using XSL for over a year. I searched the archive and FAQ but found no answer to my question. I am afraid there is not a favorable answer to my question, but here it is. I need to see if I can write a stylesheet which simply takes the input XML and turns exactly what was input into output XML. I know that you can easily do this with Xalan/DOM code, but my system requires that this situation be solved by stylesheets so that no extra code is written. Is this possible? Thank you very much. Josh Hone _________________________________________________________________ Tired of spam? Get advanced junk mail protection with MSN 8. http://join.msn.com/?page=features/junkmail XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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