Subject: RE: [xsl] How to get output XML same as input XML? From: "Robert Koberg" <rob@xxxxxxxxxx> Date: Wed, 9 Jul 2003 13:32:45 -0700 |
Hi, Why not just copy the file. Why do you need XSL? -Rob > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl- > list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Josh Hone > Sent: Wednesday, July 09, 2003 12:49 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > Hi all - > > This is my first post on this list, but I have been using XSL for over a > year. I searched the archive and FAQ but found no answer to my question. > I > am afraid there is not a favorable answer to my question, but here it is. > I > need to see if I can write a stylesheet which simply takes the input XML > and > turns exactly what was input into output XML. I know that you can easily > do > this with Xalan/DOM code, but my system requires that this situation be > solved by stylesheets so that no extra code is written. Is this possible? > > Thank you very much. > Josh Hone XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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