Subject: RE: [xsl] Sorting and re-ordering down a hierarchy From: "Cole, Chris" <chris.cole@xxxxxxxxxxxxxxxxxxxxx> Date: Fri, 18 Jul 2003 16:17:25 -0000 |
Guten Tag Dave, Thanks for your email. I think I have been trying to make my problem more complicated than it actually was - I think David Carlisle has solved it for me! Guten Abend;-) Chris > -----Original Message----- > From: David Ohlemacher [mailto:ohlemacher@xxxxxxx] > Sent: 18 July 2003 16:19 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Sorting and re-ordering down a hierarchy > > > Hi Chris, > > Sorry, I have no help. I tried to do this and failed. I finally > reevaluated the tool (DAML/XSLT Adapter > <http://www.daml.org/tools/#damlxslt>) that generated my > self-referencing data, and tossed it. I found Perl, > operating on the > DAML data directly, was SO much simpler. Also the tool's author was > not helpful. > > After a wasted week of learning XSL (it was a waste for me, no flames > please), it took me about 4 hours to write this in Perl. > The tool made > the work more difficult since it "introduced" the self > referencing. The > DAML was simpler. > > Guten Tag, > -d > > Cole, Chris wrote: > > >Hello, > > I'm struggling to re-organise my node tree. > > My tree is something like this: > > > ><input> > ><node> > > <rank>2</rank> > > <node> > > <rank>88</rank> > > </node> > > <node> > > <rank>7</rank> > > </node> > > <node> > > <rank>66</rank> > > </node> > ></node> > ><node> > > <rank>1</rank> > > <node> > > <rank>3</rank> > > </node> > > <node> > > <rank>2</rank> > > </node> > > <node> > > <rank>1</rank> > > </node> > ></node> > ></input> > > > >I need to reorganise the nodes so that they are organised in number > >order down the nodes within their tree, so the output should be like > >this: <output> <node> > > <rank>1</rank> > > <node> > > <rank>7</rank> > > </node> > > <node> > > <rank>66</rank> > > </node> > > <node> > > <rank>88</rank> > > </node> > ></node> > ><node> > > <rank>2</rank> > > <node> > > <rank>1</rank> > > </node> > > <node> > > <rank>2</rank> > > </node> > > <node> > > <rank>3</rank> > > </node> > ></node> > ></output> > >I can sort one level by using the code below, but I'm > struggling to find a > >way to re-order the second level within the first level (and > the third level > >later). > > > ><xsl:template match="/input"> > > <xsl:call-template name="ascending-numeric-sort-l1"> > > <xsl:with-param name="seqnuml1" select="node/rank"/> > > </xsl:call-template> > > > ></xsl:template> > > > ><xsl:template name="ascending-numeric-sort-l1"> > > <xsl:param name="seqnuml1"/> > > <xsl:for-each select="$seqnuml1"> > > <xsl:sort select="." data-type="number" order="ascending"/> > > <xsl:copy-of select="parent::node()"/> > > </xsl:for-each> > ></xsl:template> > > > >Can anybody offer any advice please? > >Thanks > >Chris > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > > > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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