AW: [xsl] sorting AND copying of XML via XSL

["Hendrik Beck \(Computation SIS GmbH\)" <hendrik.beck@xxxxxxxxxxxxxxxxxx>]

Hi Marcel,


> Now I want to sort the bar elements and then the item elements
according to their Id's, and finally output 
> the entire document sorted, e.g.


Think, there are better and shorter implementations do this, but this
might be one way to come by:


<xsl:output method="xml"/>

<xsl:template match="/foo">
	<xsl:element name="foo">
		<xsl:for-each select="bar">
		<xsl:sort select="@id" order="ascending"></xsl:sort>
         ^^^^^^^^^^^
			<xsl:element name="bar">
				<xsl:attribute name="id"><xsl:value-of
select="@id"/></xsl:attribute>
				
				<xsl:for-each select="item">
				<xsl:sort select="@id"
order="ascending"></xsl:sort>
                     ^^^^^^^^^^^
					<xsl:element name="item">
						<xsl:attribute
name="id"><xsl:value-of select="@id"/></xsl:attribute>
						<xsl:value-of
select="item"/>
					</xsl:element>
				</xsl:for-each>
				
			</xsl:element>
		</xsl:for-each>
	</xsl:element>
</xsl:template>


Just put two sorted for-each-loops together and produce the output via
<xsl:element> and <xsl:attribute>. This produces the exactly the xml you
wanted. Or what else problem did you have with it?


Hendrik Beck


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