Subject: RE: [xsl] Problems doing XSL Transformation using ASP From: Americo Albuquerque <melinor@xxxxxxxx> Date: Sat, 11 Oct 2003 11:12:50 +0100 |
Hi > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Mukul Gandhi > Sent: Saturday, October 11, 2003 3:38 AM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Problems doing XSL Transformation using ASP > > > The XSL file you posted, when applied to the XML, > _works fine with MSXML3.0_ . From your code, it looks > to me that you are using MSXML2.0 . MSXML2.0 does not > conform to the official W3C XSL Recommendation. I > guess MSXML2.0 supports the _W3C XSL Working Draft_ . > > But _MSXML3.0 supports W3C XSLT 1.0 and the W3C XPath > 1.0 Recommendations_. If you can try with MSXML3.0, I > think the problem will be solved. Or you can try with > MSXML4.0. It also supports W3C Recommendations.. No Rangarajan is using MSXML3. Msxml2.DomDocument is MSXML3. The error reported says: msxml3.dll error '80004005' Also an evidance that he is using MSXML3 (...) > > I have a very simple XML, XSL file and a very simple > > ASP file to perform the > > XSL Transformation on the XML file using the XSL > > file and providing it to > > any client browswer. I get the following error. > > > > NOTE: If I open the xml file (that is just from the > > client side) it works > > just fine! > > > > What am I missing??? Check if your dummy.xsl is in the same directory as the asp file Open the dummy.xsl in IE to see if it is well formed > > > > ERROR > > --------- > > > > msxml3.dll error '80004005' > > > > The stylesheet does not contain a document element. > > The stylesheet may be > > empty, or it may not be a well-formed XML document. > > > > /test/vqtreport.asp, line 9 > > > > > > ASP FILE - dummy.asp > > ------------ > > <%@ language=javascript %> > > <% > > var xslt = new > > ActiveXObject("Msxml2.XSLTemplate"); > > var xslDoc = new ActiveXObject("Msxml2.FreeThreadedDOMDocument"); > > var xslProc; > > xslDoc.async = false; > > xslDoc.resolveExternals = false; > > xslDoc.load("dummy.xsl"); Change this to: xslDoc.load(Server.MapPath("dummy.xsl")); Sometimes asp as a little trouble in finding the files Add here: if(xslDoc.parseError.errorCode!=0) { response.write("Stylesheet error:<br>"); response.write("Error: " + xslDoc.parseError.errorCode + "<br>"); response.write("Reason: " + xslDoc.parseError.reason + "<br>"); response.write("Line: " + xslDoc.parseError.line + "<br>"); response.write("Char position: " + xslDoc.parseError.linepos + "<br>"); response.write("Source: " + xslDoc.parseError.srcText + "<br>"); } This will report your error with more accuracy > > xslt.stylesheet = xslDoc; > > var xmlDoc = new > > ActiveXObject("Msxml2.DOMDocument"); > > xmlDoc.async = false; > > xmlDoc.resolveExternals = false; > > xmlDoc.load("dummy.xml"); You might want to do the same here. Just copy the above code and change xslDoc by xmlDoc > > xslProc = xslt.createProcessor(); > > xslProc.input = xmlDoc; > > xslProc.transform(); > > Response.Write(xslProc.output) > > %> (...) Regards, Americo Albuquerque XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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