Re: [xsl] XSL - using for-each with sort - can't access previous sorted nod e

[Rick Taylor <taylor@xxxxxxxx>]

Jeff,

Make sure that when you sort you specify the data-type
<xsl:sort select="@page" data-type="number"/>
or the 18 will come after the 1 and before the 2.

rick

At 04:45 PM 11/25/2003 -0500, you wrote:
> Hi all... just joined this list. Greetings :)
>
> I was wondering if someone might have an answer for me on this...
>
> Here's sample XML:
>
> <quiz>
>    <question id="1" page="4"/>
>    <question id="2" page="6"/>
>    <question id="3" page="1"/>
>    <question id="4" page="18"/>
>    <question id="5" page="7"/>
>    <question id="6" page="5"/>
> </quiz>
>
> In my XSLT, I want to sort by page. So I have:
>
> <xsl:for-each select="question">
> <xsl:sort select="@page"/>
>
> Now - as I am doing things to each question during the for-each, I want to
> be able to access the "id" attribute in the question outputted JUST PRIOR to
> the one currently being outputted. I can't seem to be able to do this. I've
> tried using position() and <xsl:number> and combinations of the two, and
> have been unsuccessful. Could anyone give me some advice?
>
> Thanks,
>
> Jeff
>
>
> ****************************************************************************
> This email may contain confidential material.
> If you were not an intended recipient,
> please notify the sender and delete all copies.
> We may monitor email to and from our network.
>
> ****************************************************************************
>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Rick Taylor
XML Developer
PPDM Association


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list