Subject: [xsl] XSL - using for-each with sort - can't access previous sorted nod e From: "Wickersty, Jeff" <Jeff.Wickersty@xxxxxxxxxxxxxxxxxxx> Date: Tue, 25 Nov 2003 16:45:15 -0500 |
Hi all... just joined this list. Greetings :) I was wondering if someone might have an answer for me on this... Here's sample XML: <quiz> <question id="1" page="4"/> <question id="2" page="6"/> <question id="3" page="1"/> <question id="4" page="18"/> <question id="5" page="7"/> <question id="6" page="5"/> </quiz> In my XSLT, I want to sort by page. So I have: <xsl:for-each select="question"> <xsl:sort select="@page"/> Now - as I am doing things to each question during the for-each, I want to be able to access the "id" attribute in the question outputted JUST PRIOR to the one currently being outputted. I can't seem to be able to do this. I've tried using position() and <xsl:number> and combinations of the two, and have been unsuccessful. Could anyone give me some advice? Thanks, Jeff **************************************************************************** This email may contain confidential material. If you were not an intended recipient, please notify the sender and delete all copies. We may monitor email to and from our network. **************************************************************************** XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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