Re: [xsl] Dynamic Tables

[jderbyshire@xxxxxxxxxxx]

I thought the were going to be equal because they are part of the same 
context.  Is there a way to compare the pair-wise unequal $unique-rooms to 
say an a sibling node with similar data?  Is context part of the select 
statement?  If I select //topics/topic/location am I in the location 
context, if so can I compare "." to //topics/place/room data?  If not, 
please explain or send some keywords about my learning deficits so I may 
be engoogled.
 
Jeff

owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx wrote on 11/25/2003 04:21:59 PM:

>> jderbyshire@xxxxxxxxxxx wrote:
>> > <topics>
>> > <topic>
>> > <name>Introduction to LotusScript for Lotus Notes and Domino</name>
>> > <start>0800</start>
>> > <end>1000</end>
>> > <location>SW 1-4</location>
>> > </topic>
>> ...
>> >  <xsl:variable name="unique-rooms" 
>> >    select="//topics/topic/location[not(. = 
>> >           preceding::location)]" /> 
>> ...
>> >                 <xsl:for-each select="$unique-rooms">
>> ...
>> >                         <xsl:if test=". = ../location">
>> ...
>> > I don't understand 
>> > why the xsl:if is always true if I am comparing 2 different things,
>> You compare two equal things. The $unique-rooms is a set of all 
location
>> elements which are pairwise unequal. The context node for the test
>> expression is such an location element. The parent of this node has 
exactly
>> one location element as child, the element which is also the context 
node.
>> Therefore both . and ../location resolve to the same node, no surprise 
that
>> the comparision of their contents is always true.
>> 
>> J.Pietschmann
>> 
>> 
>>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list