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Subject: [xsl] Dynamic Tables From: jderbyshire@xxxxxxxxxxx Date: Tue, 25 Nov 2003 15:41:55 -0600 |
Hello, Before I begin I am using: Vendor: Microsoft Vendor URL: http://www.microsoft.com I am trying to build a dynamic table from xml data using xsl:stylesheet. I am 2/3 complete. Using solutions from this list I was able to complete the first two parts. My table consists of Room Locations in the column headers, and time, start and end, at the beginning of each row. The problems begin when I try to add data to each row based on xsl:if statements. Here is an excerpt from my xml file: --Start XML <?xml version="1.0" encoding="UTF-8"?> <topics> <topic> <name>Introduction to LotusScript for Lotus Notes and Domino</name> <start>0800</start> <end>1000</end> <location>SW 1-4</location> </topic> <topic> <name>Introduction to Lotus Domino and WebSphere Integration</name> <start>0800</start> <end>1000</end> <location>DL S. Hemisphere I-II</location> </topic> <topic> <name>Integrating Lotus Domino with Corporate Data and Business Logic</name> <start>0800</start> <end>1000</end> <location>DL S. Hemisphere III-V</location> </topic> <topic> <name>Integrating Lotus Domino with Corporate Data and Business Logic</name> <start>1315</start> <end>1515</end> <location>SW 10</location> </topic> <topic> <name>Business Development Opening General Session</name> <start>0800</start> <end>1045</end> <location>Y&B GH N-S</location> </topic> <topic> <name>Tools of the Trade: Analyzing Performance of Your Lotus Domino Server</name> <start>1015</start> <end>1215</end> <location>DL S. Hemisphere III-V</location> </topic> </topics> --End XML Here is my entire xsl stylesheet: see -------notes---------- --Start XSL <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> <xsl:output method="html" /> <xsl:template match="/"> <html> <head><title>Day 1</title> </head> <body> <table border="3" width="100%"> <xsl:apply-templates select="topics" /> </table> </body> </html> </xsl:template> <xsl:template match="topics"> <xsl:variable name="unique-rooms" select="//topics/topic/location[not(. = preceding::location)]" /> <th><td>Start</td><td>End</td> <xsl:for-each select="$unique-rooms"> <xsl:sort select="." /> <td><xsl:value-of select="." /> </td> </xsl:for-each> </th> <xsl:for-each select="topic/start"> <xsl:sort select="." /> <tr><td></td> <td><xsl:value-of select="." /> </td> <td><xsl:value-of select="../end" /></td> <xsl:for-each select="$unique-rooms"> ----This is the part that doesn't work, how I want it to work--------------------- <xsl:if test=". = ../location"> ---------This xsl:if is always true, and prints the name in every column on each row------------ <td><xsl:value-of select="../name" /></td> </xsl:if> <xsl:if test=". != ../location"> <td></td> </xsl:if> </xsl:for-each> </tr> </xsl:for-each> </xsl:template> </xsl:stylesheet> --End XSL If there is more information you need please email me. I don't understand why the xsl:if is always true if I am comparing 2 different things, unless the path is changed for the ../location once it is inside the xsl:for-each select="$unique-rooms". If that is that case how to I refer to the location that is associated with the proper start time? If I test ../location outside of the xsl:for-each select="$unique-rooms" then it prints the proper location. Thanks, Jeff XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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