Subject: Re: [xsl] number of rows From: Jarkko.Moilanen@xxxxxx Date: Tue, 2 Dec 2003 11:40:10 +0200 |
Lainaus Dionisio Ruiz de Zarate <dionisio@xxxxxxxxxxxxx>: <!-- hello <!-- into oe xml i have: <!-- <!-- <nofrows>10</nofrows> <!-- the nofrows value is variable. <!-- <!-- how can i ade one thing as this using xsl: <!-- <!-- for(i=0;i<nofrows;i++){ <!-- here print <td><xsl:value-of="xxx"/></td> <!-- } <!-- <!-- how can i print one <td></td> nofrows times. <!-- <!-- <!-- canyou help me? <!-- thanks You have to use recursion / call-template something like this: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="/"> <xsl:variable name="times">10</xsl:variable> <xsl:call-template name="loop"> <xsl:with-param name="start-val" select="'1'"/> <xsl:with-param name="end-val" select="$times"/> </xsl:call-template> </xsl:template> <xsl:template name="loop"> <xsl:param name="start-val"/> <xsl:param name="end-val"/> <xsl:param name="increment" select="'1'"/> <xsl:if test="$start-val <= $end-val"> <!-- do stuff here, i just print out the number --> VALUE: <xsl:value-of select="$start-val"/> <!-- recurse --> <xsl:call-template name="loop"> <xsl:with-param name="start-val" select="$start-val + $increment"/> <xsl:with-param name="increment" select="$increment"/> <xsl:with-param name="end-val" select="$end-val"/> </xsl:call-template> </xsl:if> </xsl:template> </xsl:stylesheet> *************************************************** * Jarkko Moilanen * * Project Manager, ITCM (www.itcm.org) * * Profound XML technology Expert * * University of Tampere * * Hypermedia Laboratory * *************************************************** XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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