RE: [xsl] number of rows

["Dionisio Ruiz de Zarate" <dionisio@xxxxxxxxxxxxx>]

i am trying to print the i vale with your code but it doesn't run, doesn't
print it
the code is:
<xsl:call-template name="rec"/>
.......


  <xsl:template name="rec">
    <xsl:param name="i" select="nofrows"/>
    <xsl:if test="$i > 0 ">

        The value is: <xsl:value-of select="$i"/>

      <xsl:call-template name="rec">
        <xsl:with-param name="i" select="$i - 1"/>
      </xsl:call-template>
    </xsl:if>
  </xsl:template>


can you helpme?
thanks


> Hi,
>
>> into oe xml i have:
>>
>> <nofrows>10</nofrows>
>> the nofrows value is variable.
>>
>> how can i ade one thing as this using xsl:
>>
>> for(i=0;i<nofrows;i++){
>> here print <td><xsl:value-of="xxx"/></td>
>> }
>>
>> how can i print one <td></td> nofrows times.
>
>   <xsl:call-template name="rec"/>
>
> with the recursive template
>
>   <xsl:template name="rec">
>     <xsl:param name="i" select="nofrows"/>
>     <xsl:if test="$i >  ">
>       <td>
>         <xsl:value-of select="xxx"/>
>       </td>
>       <xsl:call-template name="rec">
>         <xsl:with-param name="i" select="$i - 1"/>
>       </xsl:call-template>
>     </xsl:if>
>   </xsl:template>
>
> Cheers,
>
> Jarno - Delerium: Remembrance
>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>


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