Re: [xsl] Line end conversion.

Subject: Re: [xsl] Line end conversion.
From: "Agnes Kielen" <agnes.kielen@xxxxxxx>
Date: Tue, 2 Dec 2003 15:25:06 +0100
Ben,
For a new line you can use &#xA; or &#xD;

Cheers,
Agnes

----- Original Message ----- 
From: "Ben Trafford" <ben@xxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, December 02, 2003 3:08 PM
Subject: [xsl] Line end conversion.


>
> Hi!
>
> I have an odd little problem. I want to match all linefeeds with a given
> element's content, and convert them to "\n". Does anybody know of a good
> way to do so?
>
> In other words...
>
> <element>This is a phrase with a line end.
>
> It's very frustrating.</element>
>
> ...becomes...
>
> <element>This is a phrase with a line end.\n\nIt's very
frustrating.</element>
>
> --->Ben
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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