RE: [xsl] Line end conversion.

[Ben Trafford <ben@xxxxxxxxxxx>]

        Thanks to everybody who answered! The problem's been solved, like so:

<xsl:template name="break">
   <xsl:param name="text" select="."/>
   <xsl:choose>
   <xsl:when test="contains($text, '&#xa;')"><xsl:value-of 
select="substring-before($text, '&#xa;')" disable-output-escaping="yes" 
/>\n<xsl:call-template name="break"><xsl:with-param name="text" 
select="substring-after($text,'&#xa;')"/></xsl:call-template></xsl:when>
   <xsl:otherwise>
        <xsl:value-of select="$text" disable-output-escaping="yes" />
   </xsl:otherwise>
   </xsl:choose>
</xsl:template>

<xsl:template select="example">
        <example><xsl:call-template name="break" /></example>
</xsl:template>


At 04:24 PM 12/2/2003 +0200, Jarno.Elovirta@xxxxxxxxx wrote:
> Write a recursive template. The FAQ has an entry for this 
> <http://www.dpawson.co.uk/xsl/sect2/replace.html#d6768e55>, but I 
> recommend writing the stylesheet yourself for educational purposes.

        The better link for this purpose is:

        http://www.dpawson.co.uk/xsl/sect2/replace.html#d6768e13

        In case anybody asks in the future. Much simpler.

--->Ben 


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