Subject: Re: [xsl] knowing the position of certain node From: "George Cristian Bina" <george@xxxxxxx> Date: Tue, 6 Jan 2004 15:21:13 +0200 |
You can just count the element on the preceding-sibling axis and add 1 to that, for instance: <xsl:value-of select="1 + count(row[field2='yes']/preceding-sibling::*)"/> Best Regards, George ------------------------------------------------------------- George Cristian Bina mailto:george@xxxxxxxxxxxxx <oXygen/> XML Editor - http://www.oxygenxml.com/ ----- Original Message ----- From: "Jaime A Stuardo Bahamondes" <jstuardo@xxxxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Tuesday, January 06, 2004 3:50 PM Subject: [xsl] knowing the position of certain node > Hi all.. > > I have this sample XML: > > <test> > <row> > <field1>this</field1> > </row> > <row> > <field1>is</field1> > </row> > <row> > <field1>a</field1> > <field2>yes</field2> > </row> > <row> > <field1>test</field1> > </row> > </test> > > > If I use <xsl:value-of select="row[field2 = 'yes']" /> I get all the third "row" field values. How can I know the position of the found node? for example, in that case, I want 3 to be printed on screen, something like "position(row[field2 = 'yes'])" > > Thanks > Jaime > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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