Subject: RE: RE: [xsl] self closing elements with attributes From: "Josh Canfield" <josh.canfield@xxxxxxxxxxxx> Date: Tue, 6 Jan 2004 13:48:37 -0800 |
You shouldn't need the xsl:output element, when I comment it out I still get correct results. without the xsl:output you should get: <foo bar="some foo"/><foo bar="some foo"/><foo bar="some foo"> foo </foo><foo bar="some foo"> foo </foo> -----Original Message----- From: annirack@xxxxxxx [mailto:annirack@xxxxxxx] Sent: Tuesday, January 06, 2004 1:15 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: RE: [xsl] self closing elements with attributes > Hmm... I'm using Xalan 2.5.2 and when I process this template: [snip] > I get: I knocked off the carriage returns in my source, and I got: <?xml version="1.0" encoding="UTF-8"?> <foo bar="some foo"/> <foo bar="some foo"/> <foo bar="some foo"> foo</foo> <foo bar="some foo"> foo</foo> > Which seems correct. What do you get? This also seems correct to me. Obviously, the template that I originally showed was not, in fact, the template I was using, it was simply a similar template. Checking further in my code, I discovered that I had not used a <xsl:output /> element. I didn't know that I needed that, but without it, my stylesheet doesn't work. Thanks, --Brendan XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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