Subject: Re: [xsl]using template match for accessing second XML file. From: Arulraj <p_arulraj@xxxxxxxxx> Date: Fri, 6 Feb 2004 03:26:56 -0800 (PST) |
Hello David, My first XML file code looks like this -------------------------------------- <table name="table4"> <label name="lefttable" rowindex="1"> <settextalign>top</settextalign> </label> <label name="Righttable" rowindex="1"> <settextalign>top</settextalign> </label> </table> My second XML file code looks like this. --------------------------------------- <field name="table4"> <row index="1"/> <assign name="strTableHtmlTmp2"value="layertable4.getTable()"/> <assign name="strTableHtmlTmp" value="strTableHtmlTmp1+ strTableHtmlTmp2 "/> </field> In my XSL file I am checking name attribute is a common field between this two XML file. so, for table4 is a common field here to access this two XML file in XSL. nametmp is the table4. In My XSL file <xsl:variable name="dataxmltmp" select="document('/data.xml')"/> long codes goes here... <xsl:apply-templates select="$dataxmltmp//field[@name=$nametmp]/assign"> <xsl:with-param name="nametmp" select="$nametmp"/> </xsl:apply-templates> long codes goes here... <xsl:template match="assign"> <xsl:param name="nametmp"/> <xsl:value-of select="$dataxmltmp//field[@name=$nametmp]/assign/@name"/> <xsl:text>=</xsl:text> <xsl:value-of select="$dataxmltmp//field[@name=$nametmp]/assign/@value"/><xsl:text>; </xsl:text> </xsl:template> I want output like this: strTableHtmlTmp2=layertable4.getTable() strTableHtmlTmp=strTableHtmlTmp1 + strTableHtmlTmp2 But I am getting output like this: strTableHtmlTmp2=layertable4.getTable() strTableHtmlTmp2=layertable4.getTable() Because I am checking only parent of this assign i.e field name attribute. So how to get a required result? Please tell me Regards Arul __________________________________ Do you Yahoo!? Yahoo! Finance: Get your refund fast by filing online. http://taxes.yahoo.com/filing.html XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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