Re: [xsl] concating strings in a loop

[Herwig Posedu <herwig.posedu@xxxxxxxxxx>]

Jarkko.Moilanen@xxxxxx wrote:

> Lainaus Jarkko.Moilanen@xxxxxx:
>
> < Lainaus Herwig Posedu <herwig.posedu@xxxxxxxxxx>:
> <
> < < hi!
> < < i want to display a list of persons "comma-seperarted" on my pdf-file.
> < < how can i concate those person-names seperated with a "," but in that
> < < way, that after the last name is no ",".
> < < i did it like this
> < <
> < < <xsl:for-each select="person">
> < < <xsl:value-of select="name" />
> < < ,<fo:inline color="white">.</fo:inline>
> < < </xsl:for-each>
> < < -> the output for example is: mike, john,
> < < -> i want to have: mike, john
> < < how can i concate the strings and substring it, so that the last comma
> < < will be removed
> <
> < <xsl:for-each select="person">
> <  <xsl:value-of select="name" />
> <  <xsl:if test="../position()!=last()">,</xsl:if>
> < </xsl:for-each>
>
> Uuups....
> Shoudl probably work better if:
>
> <xsl:for-each select="person">
>  <xsl:value-of select="name" />
>  <xsl:if test="position()!=last()">,</xsl:if>
> </xsl:for-each>
>
>
> ***************************************************
> * Jarkko Moilanen                                 *
> * Dokumentoinnin kehittäjä                        *
> * Profound XML technology Expert                  *
> * DokuMentori Oy                                  *
> * www.dokumentori.fi                              *
> ***************************************************
>
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>  
perfect, thank you. there is another question i have: is it possible to 
count the persons in the loop, so that i can say:
person1: mike, person2 joe    and so on

--
Herwig Posedu

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