RE: [xsl] position

Subject: RE: [xsl] position
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Sat, 14 Feb 2004 10:13:48 -0500
At 2004-02-14 15:54 +0100, m.vanrootseler@xxxxxxxxx wrote:
Thanks Ken, this works. I hadn't thought of using <xsl:number/>. The
output, though, starts with '0', so the first note is numbered '0' but I
solved this by putting the lot into a variable and upping it by 1.

:{)} That's the "programmer's approach" to solving the problem: throwing it in a variable and upping it by one. Many of my students come to class always trying to employ a programming approach.

May I instead suggest a hierarchical approach more consistent with XSLT:

  <xsl:if test="note">
    <xsl:for-each select="note">
      <xsl:number level="any"/>
      ...other note stuff...

That way (1) you aren't playing with variables and (2) the above note processing happens successfully when you have more than one note inside your parent element.

I hope this helps.

................... Ken

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G. Ken Holman                  mailto:gkholman@xxxxxxxxxxxxxxxxxxxx
Crane Softwrights Ltd. 
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