RE: [xsl] position

Subject: RE: [xsl] position
From: m.vanrootseler@xxxxxxxxx
Date: Sat, 14 Feb 2004 16:26:22 +0100
Hi Ken,

I'm flattered that you consider me a programmer; I'm just a humble
linguist :-) I'll try your other suggestion too as I found that upping
the number made the transformation rather slow. 



-----Oorspronkelijk bericht-----
Van: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] Namens G. Ken Holman
Verzonden: 14 februari 2004 16:14
Aan: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Onderwerp: RE: [xsl] position

At 2004-02-14 15:54 +0100, m.vanrootseler@xxxxxxxxx wrote:
>Thanks Ken, this works. I hadn't thought of using <xsl:number/>. The
>output, though, starts with '0', so the first note is numbered '0' but
>solved this by putting the lot into a variable and upping it by 1.

:{)}  That's the "programmer's approach" to solving the problem:
it in a variable and upping it by one.  Many of my students come to
always trying to employ a programming approach.

May I instead suggest a hierarchical approach more consistent with XSLT:

   <xsl:if test="note">
     <xsl:for-each select="note">
       <xsl:number level="any"/>
       ...other note stuff...

That way (1) you aren't playing with variables and (2) the above note 
processing happens successfully when you have more than one note inside 
your parent element.

I hope this helps.

................... Ken

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