Subject: [xsl] Display records in 3 columns From: "Peter Lukan" <peter.lukan@xxxxxxxx> Date: Thu, 1 Apr 2004 12:04:18 +0200 |
Hello! I'm having trouble with displaying data in 3 columns. I've managed to create a table with 3 columns : ******* XSL code *********** <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="html"/> <xsl:template match="/"> <table width="400"> <xsl:call-template name="coloredRow"> <xsl:with-param name="count" select="1"/> </xsl:call-template> </table> </xsl:template> <xsl:template name="coloredRow"> <xsl:param name="count"/> <xsl:if test="$count != count(data/objekt)"> <xsl:if test="1=($count mod 3)">#<#tr#>#</xsl:if> <td bgcolor="#ccff66"> vsebina: <xsl:value-of select="data/objekt/filename"/> </td> <xsl:if test="0=($count mod 3)">#<#/tr#>#</xsl:if> <xsl:call-template name="coloredRow"> <xsl:with-param name="count" select="$count + 1"/> </xsl:call-template> </xsl:if> </xsl:template> </xsl:stylesheet> ************* end of XSL code ************** but I can't display different records in this code <xsl:value-of select="data/objekt/filename"/> I think I should use position() function but don't know how! Thanx Peter Lukan
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