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Subject: Re: [xsl] Sort by Parameters-Child Nodes From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 29 Apr 2004 15:02:23 +0100 |
> not PERSON/FNAME or PERSON/LNAME
> when i pass them as parameters .
passing in a param (or using a variable generally) is just like using a
string in that position.
You have
<xsl:sort select="*[name()=$pa]"
<xsl:sort select="*[name()='DATE']"
works because * selects all child elements, and teh [] filters out the
date.
<xsl:sort select="*[name()='PERSON/FNAME']"
doesn't work as there is no child element with that name, what you want
is
<xsl:sort select="*/*[name()='FNAME']"
ie select a grandchild with name 'FNAME'
so
<xsl:sort select="(*|*/*)[name()=$pa]" order="{$pas}"/>
should work if you pass in pa='FNAME' or pa='DATE' as it selects either
children or grandchildren with the specified name.
David
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