Subject: Re: [xsl] Sort by Parameters-Child Nodes From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 29 Apr 2004 15:02:23 +0100 |
> not PERSON/FNAME or PERSON/LNAME > when i pass them as parameters . passing in a param (or using a variable generally) is just like using a string in that position. You have <xsl:sort select="*[name()=$pa]" <xsl:sort select="*[name()='DATE']" works because * selects all child elements, and teh [] filters out the date. <xsl:sort select="*[name()='PERSON/FNAME']" doesn't work as there is no child element with that name, what you want is <xsl:sort select="*/*[name()='FNAME']" ie select a grandchild with name 'FNAME' so <xsl:sort select="(*|*/*)[name()=$pa]" order="{$pas}"/> should work if you pass in pa='FNAME' or pa='DATE' as it selects either children or grandchildren with the specified name. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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