Subject: Re: [xsl] Sort by Parameters-Child Nodes From: Bret <laker_66@xxxxxxxxx> Date: Thu, 29 Apr 2004 08:07:02 -0700 (PDT) |
Thanks David !!!! for the detailed explanation . Thats what i was looking for . --- David Carlisle <davidc@xxxxxxxxx> wrote: > > > not PERSON/FNAME or PERSON/LNAME > > when i pass them as parameters . > > passing in a param (or using a variable generally) > is just like using a > string in that position. > > You have > > <xsl:sort select="*[name()=$pa]" > > <xsl:sort select="*[name()='DATE']" > > works because * selects all child elements, and teh > [] filters out the > date. > > > <xsl:sort select="*[name()='PERSON/FNAME']" > > doesn't work as there is no child element with that > name, what you want > is > > > <xsl:sort select="*/*[name()='FNAME']" > > ie select a grandchild with name 'FNAME' > > > so > > > <xsl:sort select="(*|*/*)[name()=$pa]" > order="{$pas}"/> > > should work if you pass in pa='FNAME' or pa='DATE' > as it selects either > children or grandchildren with the specified name. > > David > > ________________________________________________________________________ > This e-mail has been scanned for all viruses by Star > Internet. The > service is powered by MessageLabs. For more > information on a proactive > anti-virus service working around the clock, around > the globe, visit: > http://www.star.net.uk > ________________________________________________________________________ > __________________________________ Do you Yahoo!? Win a $20,000 Career Makeover at Yahoo! HotJobs http://hotjobs.sweepstakes.yahoo.com/careermakeover
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Sort by Parameters-Child , David Carlisle | Thread | [xsl] Multiple XML Files to One PDF, Patel, Viral |
RE: [xsl] Creating javascript dynam, Pieter Reint Siegers | Date | RE: AW: AW: [xsl] tomcat web server, Passin, Tom |
Month |