Subject: RE: [xsl] transformation help From: "M. David Peterson" <m.david@xxxxxxxxxx> Date: Mon, 14 Jun 2004 04:42:20 -0600 |
In yout desired output, was this intendend: <category name=3D"cat 1"> I'm assuming it was and that you already know that your attribute values need to be contained in quotes... every last bit of it. I see Michael already responded to your post but I thought I would point it out real quick, just in case. Best regards, <M:D/> -----Original Message----- From: Marcus B. Irven [mailto:marcus@xxxxxxxxxxxxxxx] Sent: Monday, June 14, 2004 3:20 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] transformation help I have an xml doc in the form of <doc> <category>cat 1</category> <item>item 1</item> <item>item 2</item> <category>cat 1</category> <item>item 3</item> <item>item 4</item> <item>item 5</item> </doc> and i want to transform it into <doc> <category name=3D"cat 1"> <item>item 1</item> <item>item 2</item> </category> <category name=3D"cat 2"> <item>item 3</item> <item>item 4</item> <item>item 5</item> </category> </doc> how should i go about this? Thanks, Marcus --+------------------------------------------------------------------ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/ or e-mail: <mailto:xsl-list-unsubscribe@xxxxxxxxxxxxxxxxxxxxxx> --+--
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