Subject: RE: [xsl] transformation help From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx> Date: Mon, 14 Jun 2004 11:46:27 +0100 |
From: "M. David Peterson" <m.david@xxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: RE: [xsl] transformation help Date: Mon, 14 Jun 2004 04:42:20 -0600
In yout desired output, was this intendend: <category name=3D"cat 1">
I'm assuming it was and that you already know that your attribute values need to be contained in quotes... every last bit of it.
I see Michael already responded to your post but I thought I would point it out real quick, just in case.
Best regards,
<M:D/>
-----Original Message----- From: Marcus B. Irven [mailto:marcus@xxxxxxxxxxxxxxx] Sent: Monday, June 14, 2004 3:20 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] transformation help
I have an xml doc in the form of
<doc> <category>cat 1</category> <item>item 1</item> <item>item 2</item> <category>cat 1</category> <item>item 3</item> <item>item 4</item> <item>item 5</item> </doc>
and i want to transform it into
<doc> <category name=3D"cat 1"> <item>item 1</item> <item>item 2</item> </category> <category name=3D"cat 2"> <item>item 3</item> <item>item 4</item> <item>item 5</item> </category> </doc>
how should i go about this?
Thanks, Marcus
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