Subject: Re: [xsl] Passing empty parameters discard parameters default value From: Thijs Janssen <thijs.janssen@xxxxxxxxx> Date: Wed, 16 Jun 2004 21:05:22 +0200 |
I'm sorry, I should've tested this *before* replying ;-) Apparantly you cannot specify an <xsl:if> inside a call-template. The only solution I can come up with this quickly is putting the entire call-template call inside an <xsl:if> but thats not really a solution if there's going to be more than one parameter. On Wed, 16 Jun 2004 20:51:20 +0200, Thijs Janssen <thijs.janssen@xxxxxxxxx> wrote: > > Hi Michal, > > The problem is that you ARE passing a parameter to mytemplate_impl. It > might eventually be empty, but it still counts as a parameter, and > thus no default value is used... (after all, one can imagine cases > where passing an empty nodeset as a parameter has a semantical > meaning) > > A possible work-around is: > > <xsl:template name="mytemplate"> > <xsl:param name="p"/> > <xsl:call-template name="mytemplate_impl"> > // parameter is not passed if its empty > <xsl:if test="$p"> > <xsl:with-param name="p" select="$p"/> > </xsl:if> > </xsl:call-template> > </xsl:template> > > regards, > Thijs Janssen > >
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