Subject: Re: [xsl] XSLT and PHP|
From: "J.Pietschmann" <j3322ptm@xxxxxxxx>
Date: Fri, 02 Jul 2004 22:41:25 +0200
By the way you know how i can resolve this please
This is the same as expecting your PHP to produce 5 as result of $ex=" + 3"; $result= 2 . $ex; The resolution of the problem depends on what exactly gets into $choice, if it's a single element name, try <xsl:for-each select="../../SELECT/*[name()=$choice]">
Check the FAQ (you've got a link already) for more on this topic, search for "evaluate".
Note further that the way you've defined the variable $choice means it holds a result tree fragment (RTF), which may trap you elswhere too. Again, check the FAQ.
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