RE: [xsl] XSLT and PHP

Subject: RE: [xsl] XSLT and PHP
From: "M. David Peterson" <m.david@xxxxxxxxxx>
Date: Fri, 2 Jul 2004 15:42:40 -0600
The list FAQ is maintained by Dave Pawson and can be found here >
http://www.dpawson.co.uk/xsl/index.html

Another really good QA type resource for XML, XSLT, and Schema is
developed and maintained by Dr. Jeni Tennison and can be found at
http://www.jenitennison.com/index.html


Best regards,
 
<M:D/>
 :: Announcing Saxon.NET (v.8.0-B) Java to C# and .NET Conversion
Project ::
 :: Be part of the project development at
http://www.x2x2x.org/x2x2x/home ::
 
 

> -----Original Message-----
> From: Pierre [mailto:pierre@xxxxxxxxxxxxx]
> Sent: Friday, July 02, 2004 3:02 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] XSLT and PHP
> 
> Sorry i've missed the FAQ link ?
> 
> Pierre
> 
> -----Message d'origine-----
> De : J.Pietschmann [mailto:j3322ptm@xxxxxxxx]
> Envoyé : vendredi 2 juillet 2004 21:41
> À : xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Objet : Re: [xsl] XSLT and PHP
> 
> Pierre wrote:
> > By the way you know how i can resolve this please
> 
> You've probably two problems. The most serious is here:
> > 		<xsl:for-each select="../../SELECT/$choice">
> 
> This is the same as expecting your PHP to produce 5 as result of
>   $ex=" + 3";
>   $result= 2 . $ex;
> The resolution of the problem depends on what exactly gets into
> $choice, if it's a single element name, try
>   <xsl:for-each select="../../SELECT/*[name()=$choice]">
> 
> Check the FAQ (you've got a link already) for more on this topic,
> search for "evaluate".
> 
> Note further that the way you've defined the variable $choice means
> it holds a result tree fragment (RTF), which may trap you elswhere
> too. Again, check the FAQ.
> 
> J.Pietschmann
> 
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