Subject: Re: [xsl] how select all siblings? From: "Hardy Merrill" <HMerrill@xxxxxxxxxxxxxxxx> Date: Wed, 13 Oct 2004 09:49:45 -0400 |
BINGO!!! Thank you very much David. >>> davidc@xxxxxxxxx 10/13/04 09:43AM >>> Any idea why the "sorted_legislators" variable only contains 1 node, and not 151 ??? if you use xsl:variable with content rather than a select attribute it _always_ generates a result tree fragment corresponding to a root node (/) with children containing whatever is generated, so if you use xx:node-set() on that you always get back a node set consisting of exactly one node, / you presumably want to access msxsl:node-set($sorted_legislators)/* David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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