Subject: [xsl] find the sum over distinct nodes From: Osman Çınar Eren <Cinar.Eren@xxxxxxxxxxxxx> Date: Thu, 18 Nov 2004 10:42:45 +0200 |
Hi, I have such an XML nodeset: <A> <B> <key>aa</key> <value> <v1>aa</v1> <v2>110</v2> </value> </B> <B> <key>bb</key> <value> <v1>bb</v1> <v2>10</v2> </value> </B> <B> <key>cc</key> <value> <v1>cc</v1> <v2>60</v2> </value> </B> </A> <A> <B> <key>bb</key> <value> <v1>bb</v1> <v2>40</v2> </value> </B> <B> <key>cc</key> <value> <v1>cc</v1> <v2>200</v2> </value> </B> </A> <A> <B> <key>dd</key> <value> <v1>dd</v1> <v2>60</v2> </value> </B> </A> what i try to do is to have the sum values over 'v2' values for distinct B nodes.(distinct means for different key values.) i would like to have such an XSL part: <xsl:for-each select="$ZZZ[generate-id(.)]/???"> <xsl:variable name="miktar" select="sum(v2)"/> <fo:table-row> <fo:table-cell> <fo:block text-align="left" font-size="8pt" > <xsl:value-of select='format-number($miktar, "###,###.00")'/> </fo:block> </fo:table-cell> </fo:table-row> where $ZZZ is the nodeset which contrains the elements given above. thanks in advance. best regards..
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