RE: [xsl] Add file name+path to processed document

["Robert Soesemann" <rsoesemann@xxxxxxxxxxx>]

Thanks for your reply. Could give an example of how to extract the path
and name of the currently processed document inside the xslt path.

By the way: I tried to iterate over the folders with ant-contribs
foreach task and the pass the current file to the xslt via its paramater
feature. But finnally I could not come over the fact that foreachs file
path was absolute and the xslt task could not work with this.See the
following example:

    <!-- ================ Target 6: AddUniqueIds  ================ -->
    <target name="6_AddUniqueIds" depends="5_Validate" >

    	<!-- Iterate over all xml files and include path as id via xslt
-->
    	<foreach target="7_sub" param="file-path" >
    		<path>
    			<fileset dir="${kiwi-xs_dir}"
includes="**/*.xml"/> <<-- ABSOLUTE PATH
    		</path>
    	</foreach>
    </target>

	<!-- Internal subtask call by foreach iterator in target 8 -->
	<target name="7_sub" >
		<echo message="${file-path}"/>
    	<xslt in="${file-path}"
    		out="????"
    		style="add-unique-id.xsl"
	  	extension=".xml">
	  		<include name="**/*.xml"/>
    			<param name="path" expression="${file-path}"/>
  		</xslt>
	</target>

-----Original Message-----
From: Emmanouil Batsis [mailto:Emmanouil.Batsis@xxxxxxxxxxx]
Sent: Montag, 29. November 2004 12:01
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Add file name+path to processed document


Robert Soesemann wrote:

>Hello,
>
>in my ANT processing pipeline I process a folder structure full of XML
>documents. One task is to add the file name and path to each processed
>file via XSL. Is there a way to extract the name and path of the
>currently processed file from the processor and write it to the output
>document. It does not need to be standard XSLT becaused inside ANT I am

>able to switch processors.
>
>

The style/xslt task accepts parameters via nested elements (see
documentation).  Just pass the base file path to each transformation. I
cannot think of a way to actually pass the file name being processed
when dealing with a fileset, but maybe you can get away with the path
(after all you probably only change the extention of the file, right?).



hth,


MAnos