Re: [xsl] Same XPath expression with diferent results

Subject: Re: [xsl] Same XPath expression with diferent results
From: xptm <xptm@xxxxxxx>
Date: Tue, 07 Dec 2004 23:44:33 +0000
My xsl is in http://gti.clientes.gtinformatica.pt/Site/Java/dmenus.xsl .. You can also see the transformation in http://gti.clientes.gtinformatica.pt/Site/Java/tap.html . It seems mine xsl it's a "combination" oh the two you show. I don't understand the firts one, toughth, specially the line

<xsl:template match="node() | attribte::*"/>

but i'll check that out.

Thanks for your input.

david_n_bertoni@xxxxxxxxxx wrote:

I don't understand this. Giving the xml in
http://gti.clientes.gtinformatica.pt/Site/Java/Menus.xml if
i inspect the xpath expression //menu (using the jEdit XPath
Tool) it gives a count 0f 8. That's what i expected.

But in

              <xsl:template match="//menu">
          blabla
              </xsl:template>

blabla only appears 3 times, corresponding to the /menus/menu.
Why this isn't giving the same 8 results?



Because the menu elements are nested, and your template does not continue the recursive processing of the source tree, you never reach the menu elements that are descendants of another menu element.


You don't show a full stylesheet, so I'm just guessing, but try these two stylesheets produce the same output, and contrast the typical "push" vs. "pull" styles:

<?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">

<xsl:template match="node() | attribte::*"/>

<xsl:template match="menu">
 <xsl:text>blabla</xsl:text>
 <xsl:apply-templates/>
</xsl:template>

</xsl:stylesheet>

<?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">

<xsl:template match="/">
 <xsl:for-each select="//menu">
   <xsl:text>blabla</xsl:text>
 </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

Note that "//" is not necessary in a match pattern.

Dave

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