Subject: Re: [xsl] xsl:sort not working within xsl:choose From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> Date: 10 Dec 2004 14:35:39 +0000 |
>>>>> "Hardy" == Hardy Merrill <HMerrill@xxxxxxxxxxxxxxxx> writes: Hardy> but that's not working - I keep getting this error: Hardy> msxml4.dll error '80004005' Hardy> Keyword xsl:sort may not be used here. Hardy> ------------------------------------ Hardy> What am I doing wrong? The thing is, if I take out the Hardy> entire choose, and just use Hardy> <xsl:sort select="code" /> Hardy> it seems to work. Well, you seem to have all but worked it out - you can't have xsl:sort anywhere except as an immediate child of xsl:for-each or xsl:apply-templates in XSLT 1.0. -- Colin Paul Adams Preston Lancashire
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