[xsl] Omitting default namespace in the output - XSLT 2.0

["Huditsch Roman" <Roman.Huditsch@xxxxxxxxxxxxx>]

Hi,

Given an example input like:

<?xml version="1.0" encoding="UTF-8"?>
<norm xmlns="myDefaultNamespace">
	<table>
		<row>
			<cell>My Table</cell>
		</row>
	</table>
</norm>

I searched for an easy way to get output data,
which is not associated to my default namespace any more,
with the help of <xsl:copy-of> in XSLT 2.0
I hoped that the attribute "copy-namespaces" set to "no" would help me
here,
but unfortunately I had no luck with Saxon 8.1.1

My output still looks like

<table>
	<row xmlns="myDefaultNamespace">
		<cell>My Table</cell>
	</row>
</table>


XSLT:
=====

	<xsl:template match="ln:table">
		<table>
			<xsl:copy-of select="node() | @*"
copy-namespaces="no"/>
		</table>
	</xsl:template>


Thanks in advance for your input!

wbr,
Roman
_______________________________________

Roman Huditsch
IT and Electronic Publishing
LexisNexis ARD Orac
Marxergasse 25
1030 Vienna
Austria
ph: +43-1-534 52-1514
f: +43-1-534 52-140
e-mail roman.huditsch@xxxxxxxxxxxxx
www.lexisnexis.at