AW: [xsl] Omitting default namespace in the output - XSLT 2.0

["Huditsch Roman" <Roman.Huditsch@xxxxxxxxxxxxx>]

I forgot to mention that the default namespace in my source document is
prefixed with "ln".
So this explaines my match pattern "ln:table".

wbr,
Roman

_______________________________________

Roman Huditsch
IT and Electronic Publishing
LexisNexis ARD Orac
Marxergasse 25
1030 Vienna
Austria
ph: +43-1-534 52-1514
f: +43-1-534 52-140
e-mail roman.huditsch@xxxxxxxxxxxxx
www.lexisnexis.at


> -----Urspr|ngliche Nachricht-----
> Von: Huditsch Roman [mailto:Roman.Huditsch@xxxxxxxxxxxxx]
> Gesendet: Montag, 20. Dezember 2004 14:52
> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff: [xsl] Omitting default namespace in the output - XSLT 2.0
>
> Hi,
>
> Given an example input like:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <norm xmlns="myDefaultNamespace">
> 	<table>
> 		<row>
> 			<cell>My Table</cell>
> 		</row>
> 	</table>
> </norm>
>
> I searched for an easy way to get output data, which is not
> associated to my default namespace any more, with the help of
> <xsl:copy-of> in XSLT 2.0 I hoped that the attribute
> "copy-namespaces" set to "no" would help me here, but
> unfortunately I had no luck with Saxon 8.1.1
>
> My output still looks like
>
> <table>
> 	<row xmlns="myDefaultNamespace">
> 		<cell>My Table</cell>
> 	</row>
> </table>
>
>
> XSLT:
> =====
>
> 	<xsl:template match="ln:table">
> 		<table>
> 			<xsl:copy-of select="node() | @*"
> copy-namespaces="no"/>
> 		</table>
> 	</xsl:template>
>
>
> Thanks in advance for your input!
>
> wbr,
> Roman
> _______________________________________
>
> Roman Huditsch
> IT and Electronic Publishing
> LexisNexis ARD Orac
> Marxergasse 25
> 1030 Vienna
> Austria
> ph: +43-1-534 52-1514
> f: +43-1-534 52-140
> e-mail roman.huditsch@xxxxxxxxxxxxx
> www.lexisnexis.at