Subject: Re: [xsl] How to retrieve value(which is copied into RTF as a variable) from RTF From: "Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx> Date: Tue, 4 Jan 2005 05:40:10 -0800 (PST) |
I could able to solve it using <xsl:value-of select="attribute::*"/> regards, Ranjan --- "Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx> wrote: > I have a RTF with following declaration > <xsl:variable name="professionLevel"> > <xsl:for-each select="//profession"> > <xsl:variable name="nameval" select="@name"/> > <xsl:variable name="parentval" select="@parent"/> > <xsl:for-each > select="exslt:node-set($leverreference)/*"> > <xsl:variable name="referid" > select="@levelref"/> > <xsl:if test="$referid=$parentval"> > <xsl:copy> > <xsl:copy-of select="$nameval"/> > </xsl:copy> > </xsl:if> > </xsl:for-each> > </xsl:for-each> > </xsl:variable> > > Later I want to retrieve $nameval from > professionLevel > RTF. > I tried with > <xsl:for-each > select="exslt:node-set($professionLevel)/*"> > <xsl:value-of select="."/> > </xsl:for-each> > but it did not work. > Any suggestion? > > regards, > Ranjan > > > > __________________________________ > Do you Yahoo!? > Dress up your holiday email, Hollywood style. Learn > more. > http://celebrity.mail.yahoo.com > > __________________________________ Do you Yahoo!? The all-new My Yahoo! - What will yours do? http://my.yahoo.com
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] How to retrieve value(which i, Ranjan K. Baisak | Thread | Re: [xsl] Namespace issue when usin, Andrew Male |
Re: [xsl] XML Date/Time service upd, Hardy Merrill | Date | Re: [xsl] How to retrieve value(whi, David Carlisle |
Month |