Subject: Re: [xsl] Usage of key inside a for loop of a RTF does not work properly From: "Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx> Date: Wed, 5 Jan 2005 02:31:01 -0800 (PST) |
> select="key('professionlevelkey','$referid')"> it was a typo, I used $referid instead '$referid'. -Ranjan --- David Carlisle <davidc@xxxxxxxxx> wrote: > > > select="key('professionlevelkey','$referid')"> > > You have used the string '$referid' as the key > value. You probably have > no key with that value. If you want the value of the > variable referid > then you want $referid not '$referid'. Although if > that is the only > place you use that variable, which seems likely then > you don't need a > variable at all, you could just use @levelref > > David > > ________________________________________________________________________ > This e-mail has been scanned for all viruses by > Star. The > service is powered by MessageLabs. For more > information on a proactive > anti-virus service working around the clock, around > the globe, visit: > http://www.star.net.uk > ________________________________________________________________________ > > __________________________________ Do you Yahoo!? Yahoo! Mail - Easier than ever with enhanced search. Learn more. http://info.mail.yahoo.com/mail_250
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