Subject: [xsl] Comparing node for identity using union From: António Mota <amsmota@xxxxxxxxx> Date: Thu, 13 Jan 2005 21:32:22 +0000 |
I don't know what's happenend in here, but i was using the union operator for comparing nodes, following M. Kay sugestion some weeks ago. It was working OK then, but now it simple stop working. I don't believe in witches, but as the Spaniards says "que las hay, hay"... What i was doing was something like this: <xsl:param name="pos" select="0"/> <xsl:variable name="snode" select="(//Menu)[$pos]"/> (...) <xsl:when test="(count(parent::Menu|$snode)=1)"> <xsl:text>1</xsl:text> </xsl:when> aplyed to something like <Menus> <Menu> <Menu_K>X00043</Menu_K> <Titulo>Processos</Titulo> <Menu> <Menu_K>X00047</Menu_K> <Titulo>Caracterizagco</Titulo> </Menu> </Menu> <Menu> <Menu_K>X00047</Menu_K> <Titulo>Caracterizagco</Titulo> </Menu> <Menu> <Menu_K>X00110</Menu_K> <Titulo>Setting's</Titulo> <Menu> <Menu_K>X00110</Menu_K> <Titulo>Setting's</Titulo> </Menu> </Menu> </Menus> In this example when the context node is /Menus/Menu/Menu and $pos=1 i want the value 1, otherwise something else. When $pos = 0 i never want that condition true, and everithing was working OK. But now i only changed the tag names and it's not working anymore. I run to the debuger i see that (count(parent::Menu|$snode)=1) is allways true, even when $snode no node, and even when there is no parent::Menu . For example, when in /Menus/Menu/Menu and (//Menu)[0] that condition is true. I'm completly lost in here, its late and i don't know what to think...
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