Subject: RE: [xsl] Reading the XML declaration using XSL From: <Jarno.Elovirta@xxxxxxxxx> Date: Thu, 20 Jan 2005 09:45:09 +0200 |
Hi, > I'd like to change the way an XML file gets rendered in a browser. > The effect that I want to achieve is what Mozilla does when one does a > "View source" - i.e. displays the XML as a text document with syntax > highlighting. I can write an XSL program to read XML and produce > syntax highlighted output, and associate the XSL to the XML via the > xml-stylesheet PI. However, if the XML file that I'm processing has an > XML declaration at the top, then I'm at a loss as to how to process > that. I've been unable to figure out a way to use XSL to read the XML > declaration and process that. Any ideas / suggestions? XPath source tree doesn't contain information about the document that was used to generate the tree (well, basedir is there but you can't access it). This applies to encoding too. A feature of XPath & XSLT. Cheers, Jarno
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