RE: [xsl] accessing parent element in if clause

["Michael Kay" <mike@xxxxxxxxxxxx>]

You want 

<xsl:if test="parent::definition">

Or better still, build this into the match pattern for the template:

<xsl:template match="definition/node">

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Rahil Qamar Yahoo [mailto:qamar_rahil@xxxxxxxxxxx] 
> Sent: 20 January 2005 12:01
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] accessing parent element in if clause
> 
> Hi
> 
> Im sure its a fairly basic question for most but Im just 
> starting out on 
> XSLT and cant find any resources to solve my problem.
> 
> I want to perform an operation based on an 'if' clause as shown below
> 
> -----------------------------------
> <xsl:template match="/">
>     <PrimeConcept><xsl:apply-templates 
> select="/archetype/definition/node"/>
>     </PrimeConcept>
> </xsl:template>
> 
> <xsl:template match="node">
>     <xsl:if test="parent::node()=definition">
>         <xsl:attribute name="id"><xsl:value-of 
> select="@id"/></xsl:attribute>
>         <xsl:attribute name="type"><xsl:value-of 
> select="@rm_class"/></xsl:attribute>
>     </xsl:if>
> </xsl:template>
> ----------------------------------
> 
> Theres a problem with the <xsl:if> statement where Im trying to 
> determine whether the <node> element is the child of the <definition> 
> element. I think theres a problem in the way Im trying to access the 
> parent node but cant figure out the right way.
> 
> Could someone please help.
> 
> Thanks
> Rahil