Re: [xsl] Relative XPATH between 2 nodes

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

This can be achieved in two different ways:

  1. Having the two nodes, then finding their first common ancestor up
in the hierarchy, then constructing the path down to the second node
from the common ancestor. This is straightforward.

  2. Using the strings (the XPath expressions ) for the two nodes.
This is much harder. For a similar solution for filenames in a tree
filesystem see:

     http://groups.google.co.uk/groups?hl=en&lr=&ie=UTF-8&oe=UTF-8&threadm=b8ujil%24dpl9r%241%40ID-152440.news.dfncis.de&rnum=1&prev=/groups%3Fq%3Dnovatchev%2Brelative%2Bpath%26hl%3Den%26lr%3D%26ie%3DUTF-8%26oe%3DUTF-8%26selm%3Db8ujil%2524dpl9r%25241%2540ID-152440.news.dfncis.de%26rnum%3D1


Cheers,
Dimitre Novatchev.


On Fri, 28 Jan 2005 09:34:33 -0500, Lyublinski, Leonid
<Leonid.Lyublinski@xxxxxxxxxxxxxxxxxxxx> wrote:
> This one should be challenging.
> 
> How to find a relative path from node A to node B if we know absolute
> paths for each of the nodes.
> I'm looking for general algorithm, logic, or idea which will help to
> avoid redundant steps.
> Maybe anybody has some prototype on this.
> Thanks
> 
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