Subject: Re: [xsl] Understanding Identity Transformations|
From: "Joris Gillis" <roac@xxxxxxxxxx>
Date: Sun, 13 Feb 2005 18:16:35 +0100
That's interesting... So you can use not(A!=B) to check if all nodes in two node-sets A and B are stingwise identical; Now isn't this a good use of '!=' ?If A is a node set with two or more nodes that are not string-equal then A != x is always true for any value of x.
regards, -- Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041) Laudeo W3C et dona ferens