RE: [xsl] != vs not(); was Understanding Identity Transformations

Subject: RE: [xsl] != vs not(); was Understanding Identity Transformations
From: "Pawson, David" <David.Pawson@xxxxxxxxxxx>
Date: Mon, 14 Feb 2005 10:53:47 -0000
    -----Original Message-----
    From: David Carlisle
    >So which would you advise to solve the question?
    >
    > "@cat and not(@cat='BLUE')"
    >
    > or
    > "@cat!='BLUE'"

    (Almost) Never used != if one or both arguments is a node
    set. Even in those cases where it does do what you want,
    you have to think so hard each time to convince yourself
    that's what you mean, that it always ends uo makin the
    stylesheet harder to debug later.

    If A is a node set with two or more nodes that are not
    string-equal then A != x is always true for any value of x.
    This is an entirely logical result of the fact that infix
    operators so an "if exists" over the whole node set, but
    it's so rarely what you want that I try to avoid != as much
    as possible.

Is this any more clear in XSLT 2.0?
I'm thinking of the changes relating to taking the first-node of a node-set
as the string value?

regards DaveP

** snip here **


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