Subject: Re: [xsl] Correction: Return Ancestor Nodes Children! From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx> Date: Fri, 18 Feb 2005 07:55:07 -0800 (PST) |
Please try - (//tree_node[@id=9]/ancestor::tree_node)/child::* (not tested!) Regards, Mukul --- Adam J Knight <adam@xxxxxxxxxxxxxxxxx> wrote: > Correction to previous post. > > Hi guys, > > Another chapter in this tragedy. > > Question: > > The expression > '//tree_node[@id=9]/ancestor::tree_node' returns a > nodeset > containing node with id(7) (its ancestor). I have > verified this with xpath > visualizer. > > How do I return the ALL children of this node also. > > The result being > Node(id=7)(ancestor) > Node(id=8) : child of Node(id=7) > Node(id=9) : child of Node(id=7) > Node(id=14) : child of Node(id=7) > > HELP APPRECIATED!!!! > > ALL TO0 FAMILIAR XML STRUCTURE: > <tree> > <tree_node id="7" value="Test Level One A"> > <tree_node id="8" value="Test Level Two A"/> > <tree_node id="9" value="Test Level Two B"> > <tree_node id="11" value="Test Level Three > B"/> > <tree_node id="10" value="Test Level Three A"> > <tree_node id="12" value="Test Level Four > A"/> > <tree_node id="13" value="Test Level Four > B"/> > </tree_node> > </tree_node> > <tree_node id="14" value="Test Level Two C"/> > </tree_node> > </tree> > > Cheers, > Adam > > NB: "Pray as if everything depended upon God and > work as if everything > depended upon man." __________________________________ Do you Yahoo!? The all-new My Yahoo! - What will yours do? http://my.yahoo.com
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