RE: [xsl] Correction: Return Ancestor Nodes Children!

["Ross, Douglas" <DRoss@xxxxxxxxxx>]

Yeah, I was temporarily confused by:
>How do I return the ALL children of this node
> also.

Douglas Ross
Developer, HTML UI Framework
Kronos
E-mail: dross@xxxxxxxxxx
www.kronos.com

-----Original Message-----
From: Mukul Gandhi [mailto:mukul_gandhi@xxxxxxxxx]
Sent: Friday, February 18, 2005 11:18 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] Correction: Return Ancestor Nodes Children!

I think Adam wanted ancestor nodes of
//tree_node[@id=9] , and all children of the
ancestors. I am not sure whether he wanted only the
root ancestor(node -> tree_node id="7") , or all the
ancestors.

I also need to correct the XPath expression I wrote(he
wanted the ancestor node as well)..

It should be -
(//tree_node[@id=9]/ancestor::tree_node)/(child::* |
self::*)

(not tested!)

Regards,
Mukul

--- "Ross, Douglas" <DRoss@xxxxxxxxxx> wrote:

> Mukul,
>
> If you just want children wouldn't you just use?
>
> //tree_node[@id=9]/child::*
>
> It seems to me that
>
> //tree_node[@id=9]/ancestor::tree_node)/child::*
>
> would find all the siblings of tree_node[@id=9] not
> its children.
>
> Note: I have not tested my suggestion either.
>
> Douglas Ross
> Developer, HTML UI Framework
> Kronos
> E-mail: dross@xxxxxxxxxx
> www.kronos.com
>
> -----Original Message-----
> From: Mukul Gandhi [mailto:mukul_gandhi@xxxxxxxxx]
> Sent: Friday, February 18, 2005 10:55 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Correction: Return Ancestor Nodes
> Children!
>
> Please try -
> (//tree_node[@id=9]/ancestor::tree_node)/child::*
>
> (not tested!)
>
> Regards,
> Mukul
>
> --- Adam J Knight <adam@xxxxxxxxxxxxxxxxx> wrote:
>
> > Correction to previous post.
> >
> > Hi guys,
> >
> > Another chapter in this tragedy.
> >
> > Question:
> >
> > The expression
> > '//tree_node[@id=9]/ancestor::tree_node' returns a
> > nodeset
> > containing node with id(7) (its ancestor). I have
> > verified this with xpath
> > visualizer.
> >
> > How do I return the ALL children of this node
> also.
> >
> > The result being
> > Node(id=7)(ancestor)
> > Node(id=8) : child of Node(id=7)
> > Node(id=9) : child of Node(id=7)
> > Node(id) : child of Node(id=7)
> >
> > HELP APPRECIATED!!!!
> >
> > ALL TO0 FAMILIAR XML STRUCTURE:
> > <tree>
> >   <tree_node id="7" value="Test Level One A">
> >     <tree_node id="8" value="Test Level Two A"/>
> >     <tree_node id="9" value="Test Level Two B">
> >       <tree_node id="11" value="Test Level Three
> > B"/>
> >       <tree_node id="10" value="Test Level Three
> A">
> >         <tree_node id="12" value="Test Level Four
> > A"/>
> >         <tree_node id="13" value="Test Level Four
> > B"/>
> >       </tree_node>
> >     </tree_node>
> >     <tree_node id="14" value="Test Level Two C"/>
> >   </tree_node>
> > </tree>
> >
> > Cheers,
> > Adam
> >
> > NB: "Pray as if everything depended upon God and
> > work as if everything
> > depended upon man."
>
>
>
>
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>




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