Re: [xsl] xslt and the filesystem

Subject: Re: [xsl] xslt and the filesystem
From: Dimitre Novatchev <dnovatchev@xxxxxxxxx>
Date: Tue, 22 Feb 2005 22:29:25 +1100
Recently there was an anouncement from Oleg Paraschenko:

"find with XPath over file system " at:

This, combined with the document() and the unparsed-text() functions
provide all the necessary functionality and flexibility to find, read
and process any (permitted) text file (xml and non-xml) in the file


Dimitre Novatchev.

On Tue, 22 Feb 2005 10:44:01 +0000, tom.kirkpatrick@xxxxxxxxxxxx
<tom.kirkpatrick@xxxxxxxxxxxx> wrote:
> Is it possible for xsl/xpath, via the document() function, to read in all
> files in a particular directory...
> Basicly I have a configuration file, which lists the directories I want to
> search in which looks like so:
> <config>
>   <category name="comments" location="/xml/articles/comments"/>
>   <category name="analysis" location="/xml/articles/analysis"/>
> <config>
> In each of those directories are a number of XML files which I would like
> to process. Up untill now I have been using Perl to read the filesystem
> and create an XML index file which I then use in my processing template to
> access all the files within that those directories.
> It would be really neet If I could just get the XSL template to look at
> everyfile in the directory, and apply appropriate processing:
> Something like:
> <xsl:template match "/">
>   <xsl:variable name="config" select="document('/global/config.xml') />
>   <xsl:for-each select="$config/config/category@location>
>      <xsl:for-each select="FILEFOUND"/>
>                ... do processing ...
>      </xsl:for-each>
>   </xsl:for-each>
> </xsl:template>
> where FILEFOUND represents somekind of wildcard which tells the processor
> to read all files fvrom the filesystem
> thanks in advance
> --
> Tom David Kirkpatrick
> Virus Bulletin Web Developer, Virus Bulletin
> Tel: +44 1235 555139
> Web:

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