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Subject: Re: [xsl] xslt and the filesystem From: Daniel Bibbens <dbibbens@xxxxxxxxxx> Date: Tue, 22 Feb 2005 07:36:46 -0800 |
tom.kirkpatrick@xxxxxxxxxxxx writes:
> Is it possible for xsl/xpath, via the document() function, to read in all
> files in a particular directory...
>
> It would be really neet If I could just get the XSL template to look at
> everyfile in the directory, and apply appropriate processing:
>
I've written an Apache (1.3.x) module, mod_rssindex, to handle this
problem. It creates an RSS 2.0 (XML) document of the files and
directories in a directory. Use
<xsl:variable
name="path"
select="document('http://yourhost.com/path/to/index.rss')/rss/channel"/>
<xsl:for-each select="$path/item[description = 'file']">
<xsl:variable name="file" select="document(link)"/>
<!-- do work with '$file' here -->
</xsl:for-each>
You can get download and installation information at:
http://xobjex.com/projects/mod_rssindex/
--
Daniel Bibbens http://xobjex.com/
Apache modules and other open-source projects for XSL & RSS
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