Subject: RE: [xsl] does xsl:output method xml guarentee well formedness? From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 11 Apr 2005 10:45:27 +0100 |
In the presence of character maps or disable-output-escaping, there is no guarantee that the serialized result of a transformation will be well-formed. This is stated at the end of the introduction to section 5 of the serialization spec, http://www.w3.org/TR/xslt-xquery-serialization/#xml-output Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: James Fuller [mailto:jim.fuller@xxxxxxxxxxxxxx] > Sent: 11 April 2005 09:38 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] does xsl:output method xml guarentee well formedness? > > for example...in XSLT 2.0 (SAXON 8.4) > > ex. XML > <?xml version="1.0" encoding="UTF-8"?> > <example> > <test>a</test> > </example> > > ex. XSLT > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > version="2.0"> > <xsl:output method="xml" indent="yes" use-character-maps="test"/> > <xsl:template match="example"> > <xsl:value-of select="test"/> > </xsl:template> > <xsl:character-map name="test"> > <xsl:output-character character="a" string="<test>"/> > </xsl:character-map> > </xsl:stylesheet> > > results in > > <?xml version="1.0" encoding="UTF-8"?><test> > > using the following stylesheet as an analogy; > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > version="2.0"> > <xsl:output method="xml" indent="yes" /> > <xsl:template match="example"> > <test> > </xsl:template> > </xsl:stylesheet> > > results in > > <?xml version="1.0" encoding="UTF-8"?> > > <test> > > which is of course well formed. > > cant really tell from the spec if xsl:output method guarentee's well > formedness or perhaps xsl:character-map needs something more ? > > --Jim Fuller
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