Subject: RE: [xsl] Having same number of rows in table irrespective of number of data rows From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Tue, 12 Apr 2005 08:59:55 +0100 |
In XSLT 2.0 you can do <xsl:for-each select="count(INITIALVALUES/INITIALVALUE)+1 to 5"> <tr>...</tr> </xsl:for-each> In 1.0 the usual approach is to select the first N nodes of some dummy node-set: <xsl:for-each select="(//node())[position() <= (5 - count(INITIALVALUES/INITIALVALUE))]" Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Steve W [mailto:lsl@xxxxxxxxxxxxx] > Sent: 12 April 2005 07:58 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Having same number of rows in table > irrespective of number of data rows > > I want to create a table that has a set number of rows in it. > The XML has > data in it to be shown in the table - in simple terms one > element of the XML > for each row of the table. The XML will only have an element > if there is > data, so if I have 3 data elements but I want 5 rows in the > table there > will be 2 'missing' rows and I want to output these 2 rows > with some set > html in it. > > My template looks like this : > > <table cellpadding="0" cellspacing="0" border="0" width="100%"> > <xsl:for-each select="INITIALVALUES/INITIALVALUE"> > <tr> > <td> > <!-- some html .... --> > </td> > </tr> > </xsl:for-each> > <!-- add 'blank' rows to give constant number of rows in table --> > </table> > > Thanks > > Steve
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