Subject: Re: [xsl] xsl:for-each...iteration question (XSLT 1.0 solution) From: JBryant@xxxxxxxxx Date: Tue, 19 Apr 2005 11:59:44 -0500 |
Sorry to reply to my own post. I realized that you won't get a well-formed XML document with my original solution. Here's the fix: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:variable name="exclude" select="document('excludedoc.xml')"/> <xsl:template match="modify"> <modify> <xsl:apply-templates/> </modify> </xsl:template> <xsl:template match="modify-attr"> <xsl:variable name="name" select="@attr-name"/> <xsl:if test="not($exclude/exclude-list/exclude-attr[.=$name])"> <xsl:copy-of select="."/> </xsl:if> </xsl:template> </xsl:stylesheet> Of course, you probably have a bunch of other templates to manage anyway, but I do like to have my answers produce well-formed output. Re-tested with Saxon 8.4 Xalan-J 2.4.1. Jay Bryant Bryant Communication Services (presently consulting at Synergistic Solution Technologies. JBryant@xxxxxxxxx 04/19/2005 11:51 AM Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx To xsl-list@xxxxxxxxxxxxxxxxxxxxxx cc Subject Re: [xsl] xsl:for-each...iteration question My solution would go like this: At the top of the stylesheet, use the document function to write the exclude-attr elements into a variable (so that I only have to use the document function once). In the modify-attr template, see if the current node has a matching exclude-attr element (by examining the contents of that variable). If not, write the modify-attr element to the result. So, I'd end up with this: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:variable name="exclude" select="document('excludedoc.xml')"/> <xsl:template match="modify-attr"> <xsl:variable name="name" select="@attr-name"/> <xsl:if test="not($exclude/exclude-list/exclude-attr[.=$name])"> <xsl:copy-of select="."/> </xsl:if> </xsl:template> </xsl:stylesheet> Tested with Saxon 8.4 and Xalan-J 2.4.1. Jay Bryant Bryant Communication Services (presently consulting at Synergistic Solution Technologies) "Paul Coletti" <pcoletti@xxxxxxxxxx> 04/19/2005 11:19 AM Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx To <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> cc Subject [xsl] xsl:for-each...iteration question This has been answered before I'm sure but doing a relevant search in the archives is tricky. I've an input doc containing a number of modify-attr elements <modify> <modify-attr attr-name = "abc"/> <modify-attr attr-name = "123"/> <modify-attr attr-name = "789"/> </modify> I have another document containing a list of prohibited attributes. <exclude-list> <exclude-attr>123</exclude-attr> </exclude-list> I want to iterate over my input doc and copy all those modify-attr elements that are NOT in the exclude list to the output. <xsl:template match="modify/modify-attr"> <xsl:variable name="currentAttr" select="@attr-name"/> <xsl:variable name="currentNode" select="."/> <xsl:for-each select="document('excludedoc')/exclude-list/exclude-attr"> <xsl:when test="$currentAttr=."> <xsl:message>Exclude</xsl:message> </xsl:when> <xsl:otherwise> <xsl:copy-of select="$currentNode"/> </xsl:otherwise> </xsl:for-each> </xsl:template> Obvisouly, this is flawed, I get multiple modify-attr elements copied to the output because I cannot see a way of ensuring the for-each only copies a permitted node once and once only. I've a feeling this is approaching the problem from the wrong way....
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